40^2+10.5^2=x^2

Solution for 40^2+10.5^2=x^2 equation:

40^2+10.5^2=x^2

We move all terms to the left:

40^2+10.5^2-(x^2)=0

We add all the numbers together, and all the variables

-1x^2+1710.25=0

a = -1; b = 0; c = +1710.25;
Δ = b2-4ac
Δ = 02-4·(-1)·1710.25
Δ = 6841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{6841}}{2*-1}=\frac{0-\sqrt{6841}}{-2}
=-\frac{\sqrt{}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{6841}}{2*-1}=\frac{0+\sqrt{6841}}{-2}
=\frac{\sqrt{}}{-2}
$